By Charles George Lamb

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If be the ohmic resistance of the coil, the maximum follows. drop of pressure will be given by the product CR. This pressure is evidently in phase with OG which represent the current, and hence if the vector OD be cut off from OC of such a length as to represent the drop on the scale selected for the pressures, the Vector Figure. coil R impressed pressure will have to supply this as well as equilibrate THE CHOKING COIL AND TRANSFORMER 53 hence it will be given by the diagonal OF of the parallelogram.

R C T or C and . s. E C Hence . v). this leads to (n and hence . is *jr B . H . v) sin -\|r =h . n v or sin . completely determined >|r = 4fe B. H' when the maximum induction The given, since that gives definitely the values of h and H. usual limits for ^r are between 45 and 30. , on reference to the curves it will be seen that the corresponding value of is 2*87 and of h is about 1800. Hence we have is H Sm * = 4 x 1800 2^5000 = ' 5 ' which gives ifr = 30 nearly. Effect of air gap. D Cunnent Fig.

Take the case where the reactance is equal to the condenser that is to say when IjFp is equal to Lp or FLp* = 1. In this case the two vertical lines being equal annul one another, and the total impedance reduces to the ohmic resistance, while the coil's impedance is 100. Thus the current with 1000 volts effect, terminal pressure will be 16f amperes, the pressure on the coil be 1666 volts, and that on the condenser will be 1333 volts. It will readily be seen that when the resistance is small, the pressures on the two parts of the circuit may be many times the terminal pressure.

### Alternating Currents -A Text-Book for Students of Engineering by Charles George Lamb

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